Base | Representation |
---|---|
bin | 100110101101011000011… |
… | …0000110101011110100011 |
3 | 200211121012100210102211102 |
4 | 1031122300300311132203 |
5 | 1144131114041320134 |
6 | 15152011502505015 |
7 | 1056236623152032 |
oct | 115326060653643 |
9 | 20747170712742 |
10 | 5320135104419 |
11 | 1771290630823 |
12 | 71b0b259516b |
13 | 2c78c0582735 |
14 | 1456d2adc719 |
15 | 935c793737e |
hex | 4d6b0c357a3 |
5320135104419 has 2 divisors, whose sum is σ = 5320135104420. Its totient is φ = 5320135104418.
The previous prime is 5320135104397. The next prime is 5320135104437. The reversal of 5320135104419 is 9144015310235.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5320135104419 - 212 = 5320135100323 is a prime.
It is a super-2 number, since 2×53201351044192 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5320138104419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2660067552209 + 2660067552210.
It is an arithmetic number, because the mean of its divisors is an integer number (2660067552210).
Almost surely, 25320135104419 is an apocalyptic number.
5320135104419 is a deficient number, since it is larger than the sum of its proper divisors (1).
5320135104419 is an equidigital number, since it uses as much as digits as its factorization.
5320135104419 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 38.
The spelling of 5320135104419 in words is "five trillion, three hundred twenty billion, one hundred thirty-five million, one hundred four thousand, four hundred nineteen".
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