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53201431 is a prime number
BaseRepresentation
bin1100101011110…
…0101000010111
310201002220122101
43022330220113
5102104421211
65140142531
71214130133
oct312745027
9121086571
1053201431
1128038028
1215997a47
13b03964a
1470cc3c3
154a0d5c1
hex32bca17

53201431 has 2 divisors, whose sum is σ = 53201432. Its totient is φ = 53201430.

The previous prime is 53201429. The next prime is 53201459. The reversal of 53201431 is 13410235.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53201431 - 21 = 53201429 is a prime.

It is a super-2 number, since 2×532014312 = 5660784520895522, which contains 22 as substring.

Together with 53201429, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 53201399 and 53201408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53201471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26600715 + 26600716.

It is an arithmetic number, because the mean of its divisors is an integer number (26600716).

Almost surely, 253201431 is an apocalyptic number.

53201431 is a deficient number, since it is larger than the sum of its proper divisors (1).

53201431 is an equidigital number, since it uses as much as digits as its factorization.

53201431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 19.

The square root of 53201431 is about 7293.9311074345. The cubic root of 53201431 is about 376.1038432624.

Adding to 53201431 its reverse (13410235), we get a palindrome (66611666).

The spelling of 53201431 in words is "fifty-three million, two hundred one thousand, four hundred thirty-one".