Base | Representation |
---|---|
bin | 100110101101100000101… |
… | …0100111011010101010000 |
3 | 200211121220201201001022212 |
4 | 1031123001110323111100 |
5 | 1144132201212013130 |
6 | 15152055231051252 |
7 | 1056246536222204 |
oct | 115330124732520 |
9 | 20747821631285 |
10 | 5320413001040 |
11 | 1771413488655 |
12 | 71b16b670b28 |
13 | 2c79360118c7 |
14 | 14571b99ab04 |
15 | 935e202be95 |
hex | 4d6c153b550 |
5320413001040 has 80 divisors (see below), whose sum is σ = 12912463549440. Its totient is φ = 2036374010880.
The previous prime is 5320413001003. The next prime is 5320413001063. The reversal of 5320413001040 is 401003140235.
It is a tau number, because it is divible by the number of its divisors (80).
It is a junction number, because it is equal to n+sod(n) for n = 5320413000997 and 5320413001015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11831684 + ... + 12273123.
It is an arithmetic number, because the mean of its divisors is an integer number (161405794368).
Almost surely, 25320413001040 is an apocalyptic number.
It is an amenable number.
5320413001040 is an abundant number, since it is smaller than the sum of its proper divisors (7592050548400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5320413001040 is a wasteful number, since it uses less digits than its factorization.
5320413001040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24104940 (or 24104934 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 5320413001040 its reverse (401003140235), we get a palindrome (5721416141275).
The spelling of 5320413001040 in words is "five trillion, three hundred twenty billion, four hundred thirteen million, one thousand, forty".
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