Base | Representation |
---|---|
bin | 11000001100101101110010… |
… | …00110011100010010100111 |
3 | 20222102011020012020111000022 |
4 | 30012112321012130102213 |
5 | 23433322124024210342 |
6 | 305101531320505355 |
7 | 14131355013006266 |
oct | 1406267106342247 |
9 | 228364205214008 |
10 | 53213455303847 |
11 | 15a56777279993 |
12 | 5b7515a61b25b |
13 | 23900130798a7 |
14 | d1d78b5ca5dd |
15 | 62430dc149d2 |
hex | 3065b919c4a7 |
53213455303847 has 2 divisors, whose sum is σ = 53213455303848. Its totient is φ = 53213455303846.
The previous prime is 53213455303843. The next prime is 53213455303909. The reversal of 53213455303847 is 74830355431235.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53213455303847 - 22 = 53213455303843 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53213455303843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26606727651923 + 26606727651924.
It is an arithmetic number, because the mean of its divisors is an integer number (26606727651924).
Almost surely, 253213455303847 is an apocalyptic number.
53213455303847 is a deficient number, since it is larger than the sum of its proper divisors (1).
53213455303847 is an equidigital number, since it uses as much as digits as its factorization.
53213455303847 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144000, while the sum is 53.
The spelling of 53213455303847 in words is "fifty-three trillion, two hundred thirteen billion, four hundred fifty-five million, three hundred three thousand, eight hundred forty-seven".
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