Base | Representation |
---|---|
bin | 100110101110110100101… |
… | …0100010100110001100111 |
3 | 200211220012011001022222212 |
4 | 1031131221110110301213 |
5 | 1144203434220243044 |
6 | 15153243031314035 |
7 | 1056406431313532 |
oct | 115355124246147 |
9 | 20756164038885 |
10 | 5323231415399 |
11 | 177262a3a3017 |
12 | 71b81751b91b |
13 | 2c7c94bb8601 |
14 | 145908015a19 |
15 | 937096a2a9e |
hex | 4d769514c67 |
5323231415399 has 2 divisors, whose sum is σ = 5323231415400. Its totient is φ = 5323231415398.
The previous prime is 5323231415387. The next prime is 5323231415401. The reversal of 5323231415399 is 9935141323235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5323231415399 - 232 = 5318936448103 is a prime.
Together with 5323231415401, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5323231415339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661615707699 + 2661615707700.
It is an arithmetic number, because the mean of its divisors is an integer number (2661615707700).
Almost surely, 25323231415399 is an apocalyptic number.
5323231415399 is a deficient number, since it is larger than the sum of its proper divisors (1).
5323231415399 is an equidigital number, since it uses as much as digits as its factorization.
5323231415399 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2624400, while the sum is 50.
The spelling of 5323231415399 in words is "five trillion, three hundred twenty-three billion, two hundred thirty-one million, four hundred fifteen thousand, three hundred ninety-nine".
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