5325113200061 has 2 divisors, whose sum is σ = 5325113200062. Its totient is φ = 5325113200060.

The previous prime is 5325113200049. The next prime is 5325113200063. The reversal of 5325113200061 is 1600023115235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3574440203161 + 1750672996900 = 1890619^2 + 1323130^2 .

It is a cyclic number.

It is not a de Polignac number, because 5325113200061 - 2¹⁰ = 5325113199037 is a prime.

Together with 5325113200063, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5325113199997 and 5325113200033.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5325113200063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662556600030 + 2662556600031.

It is an arithmetic number, because the mean of its divisors is an integer number (2662556600031).

Almost surely, 2^{5325113200061} is an apocalyptic number.

It is an amenable number.

5325113200061 is a deficient number, since it is larger than the sum of its proper divisors (1).

5325113200061 is an equidigital number, since it uses as much as digits as its factorization.

5325113200061 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 5325113200061 its reverse (1600023115235), we get a palindrome (6925136315296).

The spelling of 5325113200061 in words is "five trillion, three hundred twenty-five billion, one hundred thirteen million, two hundred thousand, sixty-one".