Base | Representation |
---|---|
bin | 100110101111110011110… |
… | …1010110111000111010111 |
3 | 200212002122212220012201211 |
4 | 1031133213222313013113 |
5 | 1144222304410034224 |
6 | 15154233235002251 |
7 | 1056513111530461 |
oct | 115374752670727 |
9 | 20762585805654 |
10 | 5325351252439 |
11 | 1773517a4aa59 |
12 | 720109439387 |
13 | 2c824213065a |
14 | 145a69787131 |
15 | 937d0837894 |
hex | 4d7e7ab71d7 |
5325351252439 has 2 divisors, whose sum is σ = 5325351252440. Its totient is φ = 5325351252438.
The previous prime is 5325351252427. The next prime is 5325351252449. The reversal of 5325351252439 is 9342521535235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5325351252439 - 223 = 5325342863831 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5325351252392 and 5325351252401.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5325351252449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662675626219 + 2662675626220.
It is an arithmetic number, because the mean of its divisors is an integer number (2662675626220).
Almost surely, 25325351252439 is an apocalyptic number.
5325351252439 is a deficient number, since it is larger than the sum of its proper divisors (1).
5325351252439 is an equidigital number, since it uses as much as digits as its factorization.
5325351252439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4860000, while the sum is 49.
The spelling of 5325351252439 in words is "five trillion, three hundred twenty-five billion, three hundred fifty-one million, two hundred fifty-two thousand, four hundred thirty-nine".
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