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5325351252449 is a prime number
BaseRepresentation
bin100110101111110011110…
…1010110111000111100001
3200212002122212220012202012
41031133213222313013201
51144222304410034244
615154233235002305
71056513111530504
oct115374752670741
920762585805665
105325351252449
111773517a4aa68
12720109439395
132c8242130667
14145a6978713b
15937d083789e
hex4d7e7ab71e1

5325351252449 has 2 divisors, whose sum is σ = 5325351252450. Its totient is φ = 5325351252448.

The previous prime is 5325351252439. The next prime is 5325351252457. The reversal of 5325351252449 is 9442521535235.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5051997952225 + 273353300224 = 2247665^2 + 522832^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5325351252449 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 5325351252397 and 5325351252406.

It is not a weakly prime, because it can be changed into another prime (5325351252439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662675626224 + 2662675626225.

It is an arithmetic number, because the mean of its divisors is an integer number (2662675626225).

Almost surely, 25325351252449 is an apocalyptic number.

It is an amenable number.

5325351252449 is a deficient number, since it is larger than the sum of its proper divisors (1).

5325351252449 is an equidigital number, since it uses as much as digits as its factorization.

5325351252449 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6480000, while the sum is 50.

The spelling of 5325351252449 in words is "five trillion, three hundred twenty-five billion, three hundred fifty-one million, two hundred fifty-two thousand, four hundred forty-nine".