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53254101360143 is a prime number
BaseRepresentation
bin11000001101111001011111…
…10010110101111000001111
320222120001010212222002010202
430012330233302311320033
523440003344422011033
6305132332454524115
714134324163540165
oct1406745762657017
9228501125862122
1053254101360143
1115a71a34982652
125b8100296663b
132393abcc32088
14d217258cd235
156253dc2b58e8
hex306f2fcb5e0f

53254101360143 has 2 divisors, whose sum is σ = 53254101360144. Its totient is φ = 53254101360142.

The previous prime is 53254101360079. The next prime is 53254101360151. The reversal of 53254101360143 is 34106310145235.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53254101360143 - 26 = 53254101360079 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53254101360097 and 53254101360106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53254101350143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26627050680071 + 26627050680072.

It is an arithmetic number, because the mean of its divisors is an integer number (26627050680072).

Almost surely, 253254101360143 is an apocalyptic number.

53254101360143 is a deficient number, since it is larger than the sum of its proper divisors (1).

53254101360143 is an equidigital number, since it uses as much as digits as its factorization.

53254101360143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 38.

The spelling of 53254101360143 in words is "fifty-three trillion, two hundred fifty-four billion, one hundred one million, three hundred sixty thousand, one hundred forty-three".