Base | Representation |
---|---|
bin | 110001100110100101… |
… | …100110001101011001 |
3 | 12002110211110220012102 |
4 | 301212211212031121 |
5 | 1333034222130132 |
6 | 40245002253145 |
7 | 3563564546444 |
oct | 614645461531 |
9 | 162424426172 |
10 | 53260739417 |
11 | 20651331916 |
12 | a3a4ab71b5 |
13 | 503a486c32 |
14 | 281380a65b |
15 | 15bac8ec62 |
hex | c66966359 |
53260739417 has 2 divisors, whose sum is σ = 53260739418. Its totient is φ = 53260739416.
The previous prime is 53260739381. The next prime is 53260739419. The reversal of 53260739417 is 71493706235.
53260739417 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51138847321 + 2121892096 = 226139^2 + 46064^2 .
It is a cyclic number.
It is not a de Polignac number, because 53260739417 - 210 = 53260738393 is a prime.
Together with 53260739419, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (53260739419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26630369708 + 26630369709.
It is an arithmetic number, because the mean of its divisors is an integer number (26630369709).
Almost surely, 253260739417 is an apocalyptic number.
It is an amenable number.
53260739417 is a deficient number, since it is larger than the sum of its proper divisors (1).
53260739417 is an equidigital number, since it uses as much as digits as its factorization.
53260739417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 952560, while the sum is 47.
The spelling of 53260739417 in words is "fifty-three billion, two hundred sixty million, seven hundred thirty-nine thousand, four hundred seventeen".
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