Base | Representation |
---|---|
bin | 1001111010111110… |
… | …01001110100001101 |
3 | 111202012211110220122 |
4 | 10331133021310031 |
5 | 41402043403031 |
6 | 2240314154325 |
7 | 245665610132 |
oct | 47537116415 |
9 | 14665743818 |
10 | 5326544141 |
11 | 22937714a6 |
12 | 1047a229a5 |
13 | 66b6c1689 |
14 | 3875c4589 |
15 | 21295a47b |
hex | 13d7c9d0d |
5326544141 has 2 divisors, whose sum is σ = 5326544142. Its totient is φ = 5326544140.
The previous prime is 5326544129. The next prime is 5326544143. The reversal of 5326544141 is 1414456235.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5056632100 + 269912041 = 71110^2 + 16429^2 .
It is a cyclic number.
It is not a de Polignac number, because 5326544141 - 214 = 5326527757 is a prime.
Together with 5326544143, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5326544143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2663272070 + 2663272071.
It is an arithmetic number, because the mean of its divisors is an integer number (2663272071).
Almost surely, 25326544141 is an apocalyptic number.
It is an amenable number.
5326544141 is a deficient number, since it is larger than the sum of its proper divisors (1).
5326544141 is an equidigital number, since it uses as much as digits as its factorization.
5326544141 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 57600, while the sum is 35.
The square root of 5326544141 is about 72983.1771095230. The cubic root of 5326544141 is about 1746.4192514471.
The spelling of 5326544141 in words is "five billion, three hundred twenty-six million, five hundred forty-four thousand, one hundred forty-one".
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