Base | Representation |
---|---|
bin | 11000001111010101100110… |
… | …10110011000110111100010 |
3 | 20222201202210021012110221111 |
4 | 30013222303112120313202 |
5 | 23441311134100242200 |
6 | 305211151514013534 |
7 | 14141024510640142 |
oct | 1407526326306742 |
9 | 228652707173844 |
10 | 53303553134050 |
11 | 15a90a0113a28a |
12 | 5b8a7041172aa |
13 | 2398671232b5b |
14 | d23c974b2922 |
15 | 6268339680ba |
hex | 307ab3598de2 |
53303553134050 has 48 divisors (see below), whose sum is σ = 104365013515200. Its totient is φ = 20198802340800.
The previous prime is 53303553133991. The next prime is 53303553134071. The reversal of 53303553134050 is 5043135530335.
It is a junction number, because it is equal to n+sod(n) for n = 53303553133994 and 53303553134012.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 44929896 + ... + 46101004.
It is an arithmetic number, because the mean of its divisors is an integer number (2174271114900).
Almost surely, 253303553134050 is an apocalyptic number.
53303553134050 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
53303553134050 is a deficient number, since it is larger than the sum of its proper divisors (51061460381150).
53303553134050 is a wasteful number, since it uses less digits than its factorization.
53303553134050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1219051 (or 1219046 counting only the distinct ones).
The product of its (nonzero) digits is 607500, while the sum is 40.
Adding to 53303553134050 its reverse (5043135530335), we get a palindrome (58346688664385).
The spelling of 53303553134050 in words is "fifty-three trillion, three hundred three billion, five hundred fifty-three million, one hundred thirty-four thousand, fifty".
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