Base | Representation |
---|---|
bin | 11000001111011000011111… |
… | …01011001110101010001101 |
3 | 20222201220210012212011022201 |
4 | 30013230033223032222031 |
5 | 23441322322114214013 |
6 | 305212005325441501 |
7 | 14141111056641151 |
oct | 1407541753165215 |
9 | 228656705764281 |
10 | 53305102101133 |
11 | 15a91626525173 |
12 | 5b8aa76a10291 |
13 | 239885a10b31c |
14 | d23da30c1061 |
15 | 6268c49363dd |
hex | 307b0facea8d |
53305102101133 has 2 divisors, whose sum is σ = 53305102101134. Its totient is φ = 53305102101132.
The previous prime is 53305102101091. The next prime is 53305102101149. The reversal of 53305102101133 is 33110120150335.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42449941991044 + 10855160110089 = 6515362^2 + 3294717^2 .
It is a cyclic number.
It is not a de Polignac number, because 53305102101133 - 229 = 53304565230221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53305102107133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26652551050566 + 26652551050567.
It is an arithmetic number, because the mean of its divisors is an integer number (26652551050567).
Almost surely, 253305102101133 is an apocalyptic number.
It is an amenable number.
53305102101133 is a deficient number, since it is larger than the sum of its proper divisors (1).
53305102101133 is an equidigital number, since it uses as much as digits as its factorization.
53305102101133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4050, while the sum is 28.
Adding to 53305102101133 its reverse (33110120150335), we get a palindrome (86415222251468).
The spelling of 53305102101133 in words is "fifty-three trillion, three hundred five billion, one hundred two million, one hundred one thousand, one hundred thirty-three".
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