Base | Representation |
---|---|
bin | 100110110010011101000… |
… | …0001100111011110011111 |
3 | 200212122022111112122011102 |
4 | 1031210322001213132133 |
5 | 1144320421121313303 |
6 | 15201012421343315 |
7 | 1060103561425166 |
oct | 115447201473637 |
9 | 20778274478142 |
10 | 5331027916703 |
11 | 1775970308925 |
12 | 721232567b3b |
13 | 2c893821aaa8 |
14 | 14604766a3dd |
15 | 93a13da2288 |
hex | 4d93a06779f |
5331027916703 has 2 divisors, whose sum is σ = 5331027916704. Its totient is φ = 5331027916702.
The previous prime is 5331027916693. The next prime is 5331027916717. The reversal of 5331027916703 is 3076197201335.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5331027916703 - 210 = 5331027915679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5331027916003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2665513958351 + 2665513958352.
It is an arithmetic number, because the mean of its divisors is an integer number (2665513958352).
Almost surely, 25331027916703 is an apocalyptic number.
5331027916703 is a deficient number, since it is larger than the sum of its proper divisors (1).
5331027916703 is an equidigital number, since it uses as much as digits as its factorization.
5331027916703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 714420, while the sum is 47.
The spelling of 5331027916703 in words is "five trillion, three hundred thirty-one billion, twenty-seven million, nine hundred sixteen thousand, seven hundred three".
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