Base | Representation |
---|---|
bin | 110001101001100110… |
… | …100011010110100110 |
3 | 12002121100122201210021 |
4 | 301221212203112212 |
5 | 1333140144242020 |
6 | 40254010345354 |
7 | 3565050520216 |
oct | 615146432646 |
9 | 162540581707 |
10 | 53311321510 |
11 | 2067793a9a7 |
12 | a3b9a2b25a |
13 | 5047ab7275 |
14 | 281a416246 |
15 | 15c04321aa |
hex | c699a35a6 |
53311321510 has 16 divisors (see below), whose sum is σ = 96178975200. Its totient is φ = 21275951616.
The previous prime is 53311321487. The next prime is 53311321517. The reversal of 53311321510 is 1512311335.
53311321510 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×533113215102 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53311321517) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6067515 + ... + 6076294.
It is an arithmetic number, because the mean of its divisors is an integer number (6011185950).
Almost surely, 253311321510 is an apocalyptic number.
53311321510 is a deficient number, since it is larger than the sum of its proper divisors (42867653690).
53311321510 is a wasteful number, since it uses less digits than its factorization.
53311321510 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12144255.
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 53311321510 its reverse (1512311335), we get a palindrome (54823632845).
The spelling of 53311321510 in words is "fifty-three billion, three hundred eleven million, three hundred twenty-one thousand, five hundred ten".
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