Base | Representation |
---|---|
bin | 100110110100011001110… |
… | …0011111100011110100000 |
3 | 200220001010021020011202201 |
4 | 1031220303203330132200 |
5 | 1144403004344124100 |
6 | 15202544053222544 |
7 | 1060312405336363 |
oct | 115506343743640 |
9 | 20801107204681 |
10 | 5335214442400 |
11 | 1777719511617 |
12 | 722000631a54 |
13 | 2c915468972b |
14 | 1463236960da |
15 | 93bab6be36a |
hex | 4da338fc7a0 |
5335214442400 has 36 divisors (see below), whose sum is σ = 13024592259462. Its totient is φ = 2134085776640.
The previous prime is 5335214442377. The next prime is 5335214442419. The reversal of 5335214442400 is 42444125335.
It can be written as a sum of positive squares in 3 ways, for example, as 4105697167504 + 1229517274896 = 2026252^2 + 1108836^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 5335214442400.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3334508227 + ... + 3334509826.
Almost surely, 25335214442400 is an apocalyptic number.
5335214442400 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
5335214442400 is an abundant number, since it is smaller than the sum of its proper divisors (7689377817062).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5335214442400 is a wasteful number, since it uses less digits than its factorization.
5335214442400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6669018073 (or 6669018060 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 37.
Adding to 5335214442400 its reverse (42444125335), we get a palindrome (5377658567735).
The spelling of 5335214442400 in words is "five trillion, three hundred thirty-five billion, two hundred fourteen million, four hundred forty-two thousand, four hundred".
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