Base | Representation |
---|---|
bin | 11000010000110110100111… |
… | …00111001001000010010101 |
3 | 20222220202012212112210200002 |
4 | 30020123103213021002111 |
5 | 23443134314301112432 |
6 | 305251123451501045 |
7 | 14144550231013364 |
oct | 1410332347110225 |
9 | 228822185483602 |
10 | 53355634004117 |
11 | 16000aa7464865 |
12 | 5b98819a57785 |
13 | 23a0551123333 |
14 | d265d830d7db |
15 | 627d80d46e62 |
hex | 3086d39c9095 |
53355634004117 has 2 divisors, whose sum is σ = 53355634004118. Its totient is φ = 53355634004116.
The previous prime is 53355634004053. The next prime is 53355634004147. The reversal of 53355634004117 is 71140043655335.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 52885969131076 + 469664873041 = 7272274^2 + 685321^2 .
It is a cyclic number.
It is not a de Polignac number, because 53355634004117 - 26 = 53355634004053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53355634004147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26677817002058 + 26677817002059.
It is an arithmetic number, because the mean of its divisors is an integer number (26677817002059).
Almost surely, 253355634004117 is an apocalyptic number.
It is an amenable number.
53355634004117 is a deficient number, since it is larger than the sum of its proper divisors (1).
53355634004117 is an equidigital number, since it uses as much as digits as its factorization.
53355634004117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268000, while the sum is 47.
The spelling of 53355634004117 in words is "fifty-three trillion, three hundred fifty-five billion, six hundred thirty-four million, four thousand, one hundred seventeen".
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