Base | Representation |
---|---|
bin | 1100101110110… |
… | …1001110101101 |
3 | 10201111000201001 |
4 | 3023231032231 |
5 | 102132303433 |
6 | 5144320301 |
7 | 1215616366 |
oct | 313551655 |
9 | 121430631 |
10 | 53400493 |
11 | 28163643 |
12 | 15a73091 |
13 | b0a9133 |
14 | 7140b6d |
15 | 4a4c57d |
hex | 32ed3ad |
53400493 has 2 divisors, whose sum is σ = 53400494. Its totient is φ = 53400492.
The previous prime is 53400481. The next prime is 53400499. The reversal of 53400493 is 39400435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29615364 + 23785129 = 5442^2 + 4877^2 .
It is a cyclic number.
It is not a de Polignac number, because 53400493 - 29 = 53399981 is a prime.
It is a super-2 number, since 2×534004932 = 5703225305286098, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53400499) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26700246 + 26700247.
It is an arithmetic number, because the mean of its divisors is an integer number (26700247).
Almost surely, 253400493 is an apocalyptic number.
It is an amenable number.
53400493 is a deficient number, since it is larger than the sum of its proper divisors (1).
53400493 is an equidigital number, since it uses as much as digits as its factorization.
53400493 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 28.
The square root of 53400493 is about 7307.5640948267. The cubic root of 53400493 is about 376.5723444440.
The spelling of 53400493 in words is "fifty-three million, four hundred thousand, four hundred ninety-three".
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