Base | Representation |
---|---|
bin | 100110110110101010000… |
… | …0110111011110001001111 |
3 | 200220111121122102222112101 |
4 | 1031231110012323301033 |
5 | 1144442413143442001 |
6 | 15205104305015531 |
7 | 1060543360263235 |
oct | 115552406736117 |
9 | 20814548388471 |
10 | 5340055452751 |
11 | 17797830a7318 |
12 | 722b319245a7 |
13 | 2c97465bc6b6 |
14 | 1466625ac955 |
15 | 93d916bca01 |
hex | 4db541bbc4f |
5340055452751 has 2 divisors, whose sum is σ = 5340055452752. Its totient is φ = 5340055452750.
The previous prime is 5340055452733. The next prime is 5340055452769. The reversal of 5340055452751 is 1572545500435.
It is a balanced prime because it is at equal distance from previous prime (5340055452733) and next prime (5340055452769).
It is a cyclic number.
It is not a de Polignac number, because 5340055452751 - 221 = 5340053355599 is a prime.
It is a super-3 number, since 3×53400554527513 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5340055452701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670027726375 + 2670027726376.
It is an arithmetic number, because the mean of its divisors is an integer number (2670027726376).
Almost surely, 25340055452751 is an apocalyptic number.
5340055452751 is a deficient number, since it is larger than the sum of its proper divisors (1).
5340055452751 is an equidigital number, since it uses as much as digits as its factorization.
5340055452751 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2100000, while the sum is 46.
The spelling of 5340055452751 in words is "five trillion, three hundred forty billion, fifty-five million, four hundred fifty-two thousand, seven hundred fifty-one".
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