Base | Representation |
---|---|
bin | 100110110110111000010… |
… | …0010011001011111100111 |
3 | 200220112211212221010222002 |
4 | 1031231300202121133213 |
5 | 1144444402244230224 |
6 | 15205223503555515 |
7 | 1060561241345135 |
oct | 115556042313747 |
9 | 20815755833862 |
10 | 5340532414439 |
11 | 17799a8358732 |
12 | 7230455bbb9b |
13 | 2c97c1369451 |
14 | 1466a9a88755 |
15 | 93dbd4d49ae |
hex | 4db708997e7 |
5340532414439 has 2 divisors, whose sum is σ = 5340532414440. Its totient is φ = 5340532414438.
The previous prime is 5340532414351. The next prime is 5340532414463. The reversal of 5340532414439 is 9344142350435.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5340532414439 - 220 = 5340531365863 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5340532414393 and 5340532414402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5340532414489) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670266207219 + 2670266207220.
It is an arithmetic number, because the mean of its divisors is an integer number (2670266207220).
Almost surely, 25340532414439 is an apocalyptic number.
5340532414439 is a deficient number, since it is larger than the sum of its proper divisors (1).
5340532414439 is an equidigital number, since it uses as much as digits as its factorization.
5340532414439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3110400, while the sum is 47.
It can be divided in two parts, 534053 and 2414439, that added together give a palindrome (2948492).
The spelling of 5340532414439 in words is "five trillion, three hundred forty billion, five hundred thirty-two million, four hundred fourteen thousand, four hundred thirty-nine".
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