Base | Representation |
---|---|
bin | 110001110000110110… |
… | …011101111011110011 |
3 | 12002220211111021221102 |
4 | 301300312131323303 |
5 | 1333412312343011 |
6 | 40314033115015 |
7 | 3601055306033 |
oct | 616066357363 |
9 | 162824437842 |
10 | 53432934131 |
11 | 2072a5532a5 |
12 | a4326b8a6b |
13 | 50670571b5 |
14 | 282c6318c3 |
15 | 15cae5573b |
hex | c70d9def3 |
53432934131 has 2 divisors, whose sum is σ = 53432934132. Its totient is φ = 53432934130.
The previous prime is 53432934103. The next prime is 53432934169. The reversal of 53432934131 is 13143923435.
It is an a-pointer prime, because the next prime (53432934169) can be obtained adding 53432934131 to its sum of digits (38).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53432934131 - 210 = 53432933107 is a prime.
It is a super-2 number, since 2×534329341312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53432934031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26716467065 + 26716467066.
It is an arithmetic number, because the mean of its divisors is an integer number (26716467066).
Almost surely, 253432934131 is an apocalyptic number.
53432934131 is a deficient number, since it is larger than the sum of its proper divisors (1).
53432934131 is an equidigital number, since it uses as much as digits as its factorization.
53432934131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 116640, while the sum is 38.
The spelling of 53432934131 in words is "fifty-three billion, four hundred thirty-two million, nine hundred thirty-four thousand, one hundred thirty-one".
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