Base | Representation |
---|---|
bin | 111100101111110110000011… |
… | …1011100010101111101001110 |
3 | 2121001221112022000021002012110 |
4 | 1321133230013130111331032 |
5 | 1030014121441042230014 |
6 | 5132241001022444450 |
7 | 220356612365333505 |
oct | 17137540734257516 |
9 | 2531845260232173 |
10 | 534341301133134 |
11 | 145291967271370 |
12 | 4bb1ab10733726 |
13 | 19c20226223481 |
14 | 95d438518d83c |
15 | 41b969bb8dd59 |
hex | 1e5fb07715f4e |
534341301133134 has 32 divisors (see below), whose sum is σ = 1197344635468416. Its totient is φ = 157545346770720.
The previous prime is 534341301133063. The next prime is 534341301133141. The reversal of 534341301133134 is 431331103143435.
It is a junction number, because it is equal to n+sod(n) for n = 534341301133092 and 534341301133101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 109406488372 + ... + 109406493255.
It is an arithmetic number, because the mean of its divisors is an integer number (37417019858388).
Almost surely, 2534341301133134 is an apocalyptic number.
534341301133134 is an abundant number, since it is smaller than the sum of its proper divisors (663003334335282).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
534341301133134 is a wasteful number, since it uses less digits than its factorization.
534341301133134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 218812981680.
The product of its (nonzero) digits is 233280, while the sum is 39.
Adding to 534341301133134 its reverse (431331103143435), we get a palindrome (965672404276569).
It can be divided in two parts, 534341301 and 133134, that added together give a palindrome (534474435).
The spelling of 534341301133134 in words is "five hundred thirty-four trillion, three hundred forty-one billion, three hundred one million, one hundred thirty-three thousand, one hundred thirty-four".
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