Base | Representation |
---|---|
bin | 111100101111110110100010… |
… | …0110110010001010111010000 |
3 | 2121001221121221210210000200012 |
4 | 1321133231010312101113100 |
5 | 1030014131043310341430 |
6 | 5132241251143414052 |
7 | 220356650045054663 |
oct | 17137550466212720 |
9 | 2531847853700605 |
10 | 534342331340240 |
11 | 1452923458471a5 |
12 | 4bb1b159754328 |
13 | 19c2035b7a8987 |
14 | 95d4441d216da |
15 | 41b970c33a695 |
hex | 1e5fb44d915d0 |
534342331340240 has 160 divisors (see below), whose sum is σ = 1283044380189696. Its totient is φ = 206855161159680.
The previous prime is 534342331340221. The next prime is 534342331340261. The reversal of 534342331340240 is 42043133243435.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 281219624 + ... + 283113336.
Almost surely, 2534342331340240 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 534342331340240, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (641522190094848).
534342331340240 is an abundant number, since it is smaller than the sum of its proper divisors (748702048849456).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
534342331340240 is a wasteful number, since it uses less digits than its factorization.
534342331340240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1894717 (or 1894711 counting only the distinct ones).
The product of its (nonzero) digits is 1244160, while the sum is 41.
Adding to 534342331340240 its reverse (42043133243435), we get a palindrome (576385464583675).
The spelling of 534342331340240 in words is "five hundred thirty-four trillion, three hundred forty-two billion, three hundred thirty-one million, three hundred forty thousand, two hundred forty".
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