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534364111013 is a prime number
BaseRepresentation
bin1111100011010101001…
…01010100000010100101
31220002021202100102110212
413301222211110002211
532223334203023023
61045252233225205
753415020000045
oct7615245240245
91802252312425
10534364111013
11196693678747
1287691562205
133b50c6bb585
141bc130c3725
15dd77956e78
hex7c6a9540a5

534364111013 has 2 divisors, whose sum is σ = 534364111014. Its totient is φ = 534364111012.

The previous prime is 534364110979. The next prime is 534364111031. The reversal of 534364111013 is 310111463435.

Together with next prime (534364111031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 524455501249 + 9908609764 = 724193^2 + 99542^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-534364111013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (534364111063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267182055506 + 267182055507.

It is an arithmetic number, because the mean of its divisors is an integer number (267182055507).

Almost surely, 2534364111013 is an apocalyptic number.

It is an amenable number.

534364111013 is a deficient number, since it is larger than the sum of its proper divisors (1).

534364111013 is an equidigital number, since it uses as much as digits as its factorization.

534364111013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 32.

Adding to 534364111013 its reverse (310111463435), we get a palindrome (844475574448).

The spelling of 534364111013 in words is "five hundred thirty-four billion, three hundred sixty-four million, one hundred eleven thousand, thirteen".