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53440400033 is a prime number
BaseRepresentation
bin110001110001010010…
…111100101010100001
312002221100112121020022
4301301102330222201
51333421220300113
640314501123225
73601205622356
oct616122745241
9162840477208
1053440400033
1120733792569
12a4350b9515
13506876c4a7
14282d61662d
1515cb92c908
hexc714bcaa1

53440400033 has 2 divisors, whose sum is σ = 53440400034. Its totient is φ = 53440400032.

The previous prime is 53440400029. The next prime is 53440400089. The reversal of 53440400033 is 33000404435.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31177671184 + 22262728849 = 176572^2 + 149207^2 .

It is a cyclic number.

It is not a de Polignac number, because 53440400033 - 22 = 53440400029 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 53440399975 and 53440400011.

It is not a weakly prime, because it can be changed into another prime (53440430033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26720200016 + 26720200017.

It is an arithmetic number, because the mean of its divisors is an integer number (26720200017).

Almost surely, 253440400033 is an apocalyptic number.

It is an amenable number.

53440400033 is a deficient number, since it is larger than the sum of its proper divisors (1).

53440400033 is an equidigital number, since it uses as much as digits as its factorization.

53440400033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 26.

Adding to 53440400033 its reverse (33000404435), we get a palindrome (86440804468).

The spelling of 53440400033 in words is "fifty-three billion, four hundred forty million, four hundred thousand, thirty-three".