Search a number
-
+
5344212437 is a prime number
BaseRepresentation
bin1001111101000101…
…00011010111010101
3111210110002010020222
410332202203113111
541421104244222
62242145004125
7246302025164
oct47642432725
914713063228
105344212437
1122a27399a3
121051923645
136722696a5
14389aa33db
1521429a542
hex13e8a35d5

5344212437 has 2 divisors, whose sum is σ = 5344212438. Its totient is φ = 5344212436.

The previous prime is 5344212407. The next prime is 5344212439. The reversal of 5344212437 is 7342124435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5056774321 + 287438116 = 71111^2 + 16954^2 .

It is a cyclic number.

It is not a de Polignac number, because 5344212437 - 210 = 5344211413 is a prime.

Together with 5344212439, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 5344212397 and 5344212406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5344212439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2672106218 + 2672106219.

It is an arithmetic number, because the mean of its divisors is an integer number (2672106219).

Almost surely, 25344212437 is an apocalyptic number.

It is an amenable number.

5344212437 is a deficient number, since it is larger than the sum of its proper divisors (1).

5344212437 is an equidigital number, since it uses as much as digits as its factorization.

5344212437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 80640, while the sum is 35.

The square root of 5344212437 is about 73104.1205199816. The cubic root of 5344212437 is about 1748.3480941873.

The spelling of 5344212437 in words is "five billion, three hundred forty-four million, two hundred twelve thousand, four hundred thirty-seven".