Base | Representation |
---|---|
bin | 1001111101000101… |
… | …00011010111010101 |
3 | 111210110002010020222 |
4 | 10332202203113111 |
5 | 41421104244222 |
6 | 2242145004125 |
7 | 246302025164 |
oct | 47642432725 |
9 | 14713063228 |
10 | 5344212437 |
11 | 22a27399a3 |
12 | 1051923645 |
13 | 6722696a5 |
14 | 389aa33db |
15 | 21429a542 |
hex | 13e8a35d5 |
5344212437 has 2 divisors, whose sum is σ = 5344212438. Its totient is φ = 5344212436.
The previous prime is 5344212407. The next prime is 5344212439. The reversal of 5344212437 is 7342124435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5056774321 + 287438116 = 71111^2 + 16954^2 .
It is a cyclic number.
It is not a de Polignac number, because 5344212437 - 210 = 5344211413 is a prime.
Together with 5344212439, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 5344212397 and 5344212406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5344212439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2672106218 + 2672106219.
It is an arithmetic number, because the mean of its divisors is an integer number (2672106219).
Almost surely, 25344212437 is an apocalyptic number.
It is an amenable number.
5344212437 is a deficient number, since it is larger than the sum of its proper divisors (1).
5344212437 is an equidigital number, since it uses as much as digits as its factorization.
5344212437 is an evil number, because the sum of its binary digits is even.
The product of its digits is 80640, while the sum is 35.
The square root of 5344212437 is about 73104.1205199816. The cubic root of 5344212437 is about 1748.3480941873.
The spelling of 5344212437 in words is "five billion, three hundred forty-four million, two hundred twelve thousand, four hundred thirty-seven".
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