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53443444434407 is a prime number
BaseRepresentation
bin11000010011011010001011…
…00001010110010111100111
321000020010212112100211210222
430021231011201112113213
524001104133233400112
6305355325054034555
714154106242241646
oct1411550541262747
9230203775324728
1053443444434407
111603526812a805
125bb18454a8a5b
1323a8906426621
14d2a9684c735d
1562a2bed67372
hex309b458565e7

53443444434407 has 2 divisors, whose sum is σ = 53443444434408. Its totient is φ = 53443444434406.

The previous prime is 53443444434349. The next prime is 53443444434551. The reversal of 53443444434407 is 70443444434435.

53443444434407 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 53443444434407 - 232 = 53439149467111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53443444430407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26721722217203 + 26721722217204.

It is an arithmetic number, because the mean of its divisors is an integer number (26721722217204).

Almost surely, 253443444434407 is an apocalyptic number.

53443444434407 is a deficient number, since it is larger than the sum of its proper divisors (1).

53443444434407 is an equidigital number, since it uses as much as digits as its factorization.

53443444434407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 61931520, while the sum is 53.

The spelling of 53443444434407 in words is "fifty-three trillion, four hundred forty-three billion, four hundred forty-four million, four hundred thirty-four thousand, four hundred seven".