Base | Representation |
---|---|
bin | 1100101111111… |
… | …1001011100101 |
3 | 10201121202120022 |
4 | 3023333023211 |
5 | 102142132041 |
6 | 5150044525 |
7 | 1216343636 |
oct | 313771345 |
9 | 121552508 |
10 | 53474021 |
11 | 28203907 |
12 | 15aa9745 |
13 | b103743 |
14 | 715d88d |
15 | 4a6424b |
hex | 32ff2e5 |
53474021 has 2 divisors, whose sum is σ = 53474022. Its totient is φ = 53474020.
The previous prime is 53474017. The next prime is 53474023. The reversal of 53474021 is 12047435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47761921 + 5712100 = 6911^2 + 2390^2 .
It is a cyclic number.
It is not a de Polignac number, because 53474021 - 22 = 53474017 is a prime.
It is a super-3 number, since 3×534740213 (a number of 24 digits) contains 333 as substring.
Together with 53474023, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53474023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26737010 + 26737011.
It is an arithmetic number, because the mean of its divisors is an integer number (26737011).
Almost surely, 253474021 is an apocalyptic number.
It is an amenable number.
53474021 is a deficient number, since it is larger than the sum of its proper divisors (1).
53474021 is an equidigital number, since it uses as much as digits as its factorization.
53474021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3360, while the sum is 26.
The square root of 53474021 is about 7312.5933156439. The cubic root of 53474021 is about 376.7451013557.
The spelling of 53474021 in words is "fifty-three million, four hundred seventy-four thousand, twenty-one".
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