Base | Representation |
---|---|
bin | 1001111110001000… |
… | …00100110011011001 |
3 | 111211001121120201221 |
4 | 10333010010303121 |
5 | 41430332001103 |
6 | 2243101212041 |
7 | 246436515304 |
oct | 47704046331 |
9 | 14731546657 |
10 | 5353000153 |
11 | 22a76a1276 |
12 | 1054861021 |
13 | 674025517 |
14 | 38ad0db3b |
15 | 214e341bd |
hex | 13f104cd9 |
5353000153 has 2 divisors, whose sum is σ = 5353000154. Its totient is φ = 5353000152.
The previous prime is 5353000129. The next prime is 5353000183. The reversal of 5353000153 is 3510003535.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5050518489 + 302481664 = 71067^2 + 17392^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5353000153 is a prime.
It is a super-2 number, since 2×53530001532 = 57309221276036046818, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5353000183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2676500076 + 2676500077.
It is an arithmetic number, because the mean of its divisors is an integer number (2676500077).
Almost surely, 25353000153 is an apocalyptic number.
It is an amenable number.
5353000153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5353000153 is an equidigital number, since it uses as much as digits as its factorization.
5353000153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3375, while the sum is 25.
The square root of 5353000153 is about 73164.1999409547. The cubic root of 5353000153 is about 1749.3058638098.
Adding to 5353000153 its reverse (3510003535), we get a palindrome (8863003688).
The spelling of 5353000153 in words is "five billion, three hundred fifty-three million, one hundred fifty-three", and thus it is an aban number.
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