53612715437 has 2 divisors, whose sum is σ = 53612715438. Its totient is φ = 53612715436.

The previous prime is 53612715389. The next prime is 53612715439. The reversal of 53612715437 is 73451721635.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44695879396 + 8916836041 = 211414^2 + 94429^2 .

It is a cyclic number.

It is not a de Polignac number, because 53612715437 - 2⁸ = 53612715181 is a prime.

Together with 53612715439, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53612715439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26806357718 + 26806357719.

It is an arithmetic number, because the mean of its divisors is an integer number (26806357719).

Almost surely, 2^53612715437 is an apocalyptic number.

It is an amenable number.

53612715437 is a deficient number, since it is larger than the sum of its proper divisors (1).

53612715437 is an equidigital number, since it uses as much as digits as its factorization.

53612715437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 529200, while the sum is 44.

The spelling of 53612715437 in words is "fifty-three billion, six hundred twelve million, seven hundred fifteen thousand, four hundred thirty-seven".