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53619426137 is a prime number
BaseRepresentation
bin110001111011111101…
…111000001101011001
312010101211102001212202
4301323331320031121
51334303033114022
640344334215545
73605511413354
oct617375701531
9163354361782
1053619426137
112081584a522
12a4850545b5
135096891cb4
1428492d929b
1515dc4e2592
hexc7bf78359

53619426137 has 2 divisors, whose sum is σ = 53619426138. Its totient is φ = 53619426136.

The previous prime is 53619426097. The next prime is 53619426139. The reversal of 53619426137 is 73162491635.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32436370201 + 21183055936 = 180101^2 + 145544^2 .

It is a cyclic number.

It is not a de Polignac number, because 53619426137 - 210 = 53619425113 is a prime.

It is a super-2 number, since 2×536194261372 (a number of 22 digits) contains 22 as substring.

Together with 53619426139, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 53619426091 and 53619426100.

It is not a weakly prime, because it can be changed into another prime (53619426139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26809713068 + 26809713069.

It is an arithmetic number, because the mean of its divisors is an integer number (26809713069).

Almost surely, 253619426137 is an apocalyptic number.

It is an amenable number.

53619426137 is a deficient number, since it is larger than the sum of its proper divisors (1).

53619426137 is an equidigital number, since it uses as much as digits as its factorization.

53619426137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 816480, while the sum is 47.

The spelling of 53619426137 in words is "fifty-three billion, six hundred nineteen million, four hundred twenty-six thousand, one hundred thirty-seven".