Base | Representation |
---|---|
bin | 100111000001000001001… |
… | …1011011001110110001101 |
3 | 200222122001102102101121010 |
4 | 1032002002123121312031 |
5 | 1200324001144012440 |
6 | 15223224321355433 |
7 | 1062261655624155 |
oct | 116020233316615 |
9 | 20878042371533 |
10 | 5362307407245 |
11 | 1788161811058 |
12 | 727301a98b79 |
13 | 2cb8816b9889 |
14 | 1477739b7765 |
15 | 94744eb9580 |
hex | 4e0826d9d8d |
5362307407245 has 64 divisors (see below), whose sum is σ = 9484969342464. Its totient is φ = 2573113466880.
The previous prime is 5362307407139. The next prime is 5362307407271. The reversal of 5362307407245 is 5427047032635.
5362307407245 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5362307407245 - 212 = 5362307403149 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5362307407194 and 5362307407203.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 9659425 + ... + 10199465.
It is an arithmetic number, because the mean of its divisors is an integer number (148202645976).
Almost surely, 25362307407245 is an apocalyptic number.
It is an amenable number.
5362307407245 is a deficient number, since it is larger than the sum of its proper divisors (4122661935219).
5362307407245 is a wasteful number, since it uses less digits than its factorization.
5362307407245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 541782.
The product of its (nonzero) digits is 4233600, while the sum is 48.
The spelling of 5362307407245 in words is "five trillion, three hundred sixty-two billion, three hundred seven million, four hundred seven thousand, two hundred forty-five".
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