Base | Representation |
---|---|
bin | 110001111100001100… |
… | …000000111111100010 |
3 | 12010102002101100112202 |
4 | 301330030000333202 |
5 | 1334310010212010 |
6 | 40344545453202 |
7 | 3605555050121 |
oct | 617414007742 |
9 | 163362340482 |
10 | 53623132130 |
11 | 20817950927 |
12 | a486341202 |
13 | 509758baa9 |
14 | 28499c1ab8 |
15 | 15dc9c56a5 |
hex | c7c300fe2 |
53623132130 has 48 divisors (see below), whose sum is σ = 104468256360. Its totient is φ = 19806578688.
The previous prime is 53623132127. The next prime is 53623132133. The reversal of 53623132130 is 3123132635.
It is an interprime number because it is at equal distance from previous prime (53623132127) and next prime (53623132133).
It can be written as a sum of positive squares in 12 ways, for example, as 34212791089 + 19410341041 = 184967^2 + 139321^2 .
It is a junction number, because it is equal to n+sod(n) for n = 53623132093 and 53623132102.
It is not an unprimeable number, because it can be changed into a prime (53623132133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 21875 + ... + 328214.
Almost surely, 253623132130 is an apocalyptic number.
53623132130 is a deficient number, since it is larger than the sum of its proper divisors (50845124230).
53623132130 is a wasteful number, since it uses less digits than its factorization.
53623132130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 350183 (or 350166 counting only the distinct ones).
The product of its (nonzero) digits is 9720, while the sum is 29.
Adding to 53623132130 its reverse (3123132635), we get a palindrome (56746264765).
The spelling of 53623132130 in words is "fifty-three billion, six hundred twenty-three million, one hundred thirty-two thousand, one hundred thirty".
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