Base | Representation |
---|---|
bin | 100111000001000001101… |
… | …1110100100101010111111 |
3 | 200222122002122112222012202 |
4 | 1032002003132210222333 |
5 | 1200324020200441411 |
6 | 15223230151022115 |
7 | 1062262261401332 |
oct | 116020336445277 |
9 | 20878078488182 |
10 | 5362325015231 |
11 | 1788170748208 |
12 | 72730796a93b |
13 | 2cb8852432c2 |
14 | 14777607c619 |
15 | 947467e683b |
hex | 4e0837a4abf |
5362325015231 has 2 divisors, whose sum is σ = 5362325015232. Its totient is φ = 5362325015230.
The previous prime is 5362325015219. The next prime is 5362325015261. The reversal of 5362325015231 is 1325105232635.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5362325015231 - 26 = 5362325015167 is a prime.
It is a super-2 number, since 2×53623250152312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5362325015261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2681162507615 + 2681162507616.
It is an arithmetic number, because the mean of its divisors is an integer number (2681162507616).
Almost surely, 25362325015231 is an apocalyptic number.
5362325015231 is a deficient number, since it is larger than the sum of its proper divisors (1).
5362325015231 is an equidigital number, since it uses as much as digits as its factorization.
5362325015231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 38.
The spelling of 5362325015231 in words is "five trillion, three hundred sixty-two billion, three hundred twenty-five million, fifteen thousand, two hundred thirty-one".
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