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536241521141 is a prime number
BaseRepresentation
bin1111100110110100111…
…11000100000111110101
31220021010121000202000022
413303122133010013311
532241210312134031
61050202420454525
753512364503004
oct7633237040765
91807117022008
10536241521141
111974673a4767
1287b1624a445
133b74b642c41
141bd5058ac3b
15de376a197b
hex7cda7c41f5

536241521141 has 2 divisors, whose sum is σ = 536241521142. Its totient is φ = 536241521140.

The previous prime is 536241521077. The next prime is 536241521281. The reversal of 536241521141 is 141125142635.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 291523325041 + 244718196100 = 539929^2 + 494690^2 .

It is a cyclic number.

It is not a de Polignac number, because 536241521141 - 26 = 536241521077 is a prime.

It is a super-2 number, since 2×5362415211412 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (536241521741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268120760570 + 268120760571.

It is an arithmetic number, because the mean of its divisors is an integer number (268120760571).

Almost surely, 2536241521141 is an apocalyptic number.

It is an amenable number.

536241521141 is a deficient number, since it is larger than the sum of its proper divisors (1).

536241521141 is an equidigital number, since it uses as much as digits as its factorization.

536241521141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 28800, while the sum is 35.

Adding to 536241521141 its reverse (141125142635), we get a palindrome (677366663776).

The spelling of 536241521141 in words is "five hundred thirty-six billion, two hundred forty-one million, five hundred twenty-one thousand, one hundred forty-one".