Base | Representation |
---|---|
bin | 1111100111001100000… |
… | …01100111111010111000 |
3 | 1220021122002100002111021 |
4 | 13303212001213322320 |
5 | 32242104343130130 |
6 | 1050233534312224 |
7 | 53520235241305 |
oct | 7634601477270 |
9 | 1807562302437 |
10 | 536435130040 |
11 | 197556711a17 |
12 | 87b6b058674 |
13 | 3b77c7a0214 |
14 | 1bd6c1880ac |
15 | de4969737a |
hex | 7ce6067eb8 |
536435130040 has 16 divisors (see below), whose sum is σ = 1206979042680. Its totient is φ = 214574052000.
The previous prime is 536435129957. The next prime is 536435130053. The reversal of 536435130040 is 40031534635.
It is a junction number, because it is equal to n+sod(n) for n = 536435129978 and 536435130005.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6705439086 + ... + 6705439165.
Almost surely, 2536435130040 is an apocalyptic number.
It is an amenable number.
536435130040 is an abundant number, since it is smaller than the sum of its proper divisors (670543912640).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
536435130040 is a wasteful number, since it uses less digits than its factorization.
536435130040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13410878262 (or 13410878258 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 536435130040 its reverse (40031534635), we get a palindrome (576466664675).
The spelling of 536435130040 in words is "five hundred thirty-six billion, four hundred thirty-five million, one hundred thirty thousand, forty".
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