Base | Representation |
---|---|
bin | 100111000010111001011… |
… | …1000010111100110011111 |
3 | 201000000110120100011111102 |
4 | 1032011302320113212133 |
5 | 1200410231413011223 |
6 | 15225132510543315 |
7 | 1062463642256051 |
oct | 116056270274637 |
9 | 21000416304442 |
10 | 5366341532063 |
11 | 1789941992806 |
12 | 728048b07b3b |
13 | 2cc0753c8895 |
14 | 147a376918d1 |
15 | 948ce230928 |
hex | 4e172e1799f |
5366341532063 has 2 divisors, whose sum is σ = 5366341532064. Its totient is φ = 5366341532062.
The previous prime is 5366341532033. The next prime is 5366341532107. The reversal of 5366341532063 is 3602351436635.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5366341532063 - 216 = 5366341466527 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5366341531999 and 5366341532017.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5366341532033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2683170766031 + 2683170766032.
It is an arithmetic number, because the mean of its divisors is an integer number (2683170766032).
Almost surely, 25366341532063 is an apocalyptic number.
5366341532063 is a deficient number, since it is larger than the sum of its proper divisors (1).
5366341532063 is an equidigital number, since it uses as much as digits as its factorization.
5366341532063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3499200, while the sum is 47.
Adding to 5366341532063 its reverse (3602351436635), we get a palindrome (8968692968698).
The spelling of 5366341532063 in words is "five trillion, three hundred sixty-six billion, three hundred forty-one million, five hundred thirty-two thousand, sixty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •