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53674836701 is a prime number
BaseRepresentation
bin110001111111010001…
…010000001011011101
312010112200200012212212
4301333101100023131
51334411224233301
640354034010205
73610053404243
oct617721201335
9163480605785
1053674836701
1120844056282
12a49b716965
1350a51c3005
142852800793
1515e22da4bb
hexc7f4502dd

53674836701 has 2 divisors, whose sum is σ = 53674836702. Its totient is φ = 53674836700.

The previous prime is 53674836689. The next prime is 53674836703. The reversal of 53674836701 is 10763847635.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 52600963801 + 1073872900 = 229349^2 + 32770^2 .

It is a cyclic number.

It is not a de Polignac number, because 53674836701 - 222 = 53670642397 is a prime.

Together with 53674836703, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53674836701.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53674836703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26837418350 + 26837418351.

It is an arithmetic number, because the mean of its divisors is an integer number (26837418351).

Almost surely, 253674836701 is an apocalyptic number.

It is an amenable number.

53674836701 is a deficient number, since it is larger than the sum of its proper divisors (1).

53674836701 is an equidigital number, since it uses as much as digits as its factorization.

53674836701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2540160, while the sum is 50.

The spelling of 53674836701 in words is "fifty-three billion, six hundred seventy-four million, eight hundred thirty-six thousand, seven hundred one".