Base | Representation |
---|---|
bin | 110001111111010011… |
… | …100101010000110110 |
3 | 12010112201211020112111 |
4 | 301333103211100312 |
5 | 1334411403303400 |
6 | 40354055041234 |
7 | 3610061526460 |
oct | 617723452066 |
9 | 163481736474 |
10 | 53675447350 |
11 | 20844433048 |
12 | a49b97021a |
13 | 50a5377c45 |
14 | 285291d130 |
15 | 15e23ab3ba |
hex | c7f4e5436 |
53675447350 has 48 divisors (see below), whose sum is σ = 114159130848. Its totient is φ = 18393258240.
The previous prime is 53675447347. The next prime is 53675447359. The reversal of 53675447350 is 5374457635.
It is a junction number, because it is equal to n+sod(n) for n = 53675447294 and 53675447303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53675447359) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 636882 + ... + 716218.
It is an arithmetic number, because the mean of its divisors is an integer number (2378315226).
Almost surely, 253675447350 is an apocalyptic number.
53675447350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
53675447350 is an abundant number, since it is smaller than the sum of its proper divisors (60483683498).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53675447350 is a wasteful number, since it uses less digits than its factorization.
53675447350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81289 (or 81284 counting only the distinct ones).
The product of its (nonzero) digits is 5292000, while the sum is 49.
The spelling of 53675447350 in words is "fifty-three billion, six hundred seventy-five million, four hundred forty-seven thousand, three hundred fifty".
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