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536775122550113 is a prime number
BaseRepresentation
bin111101000001100011011001…
…0100000001111110101100001
32121101120012102012122022010122
41322003012302200033311201
51030324010422333100423
65141343030450210025
7221030502634131026
oct17203066240176541
92541505365568118
10536775122550113
11146040061a87727
1250252746583915
131a0688a50b3735
14967a0a999554d
15420cb458da8c8
hex1e831b280fd61

536775122550113 has 2 divisors, whose sum is σ = 536775122550114. Its totient is φ = 536775122550112.

The previous prime is 536775122550071. The next prime is 536775122550143. The reversal of 536775122550113 is 311055221577635.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 461528397836944 + 75246724713169 = 21483212^2 + 8674487^2 .

It is a cyclic number.

It is not a de Polignac number, because 536775122550113 - 214 = 536775122533729 is a prime.

It is not a weakly prime, because it can be changed into another prime (536775122550143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268387561275056 + 268387561275057.

It is an arithmetic number, because the mean of its divisors is an integer number (268387561275057).

Almost surely, 2536775122550113 is an apocalyptic number.

It is an amenable number.

536775122550113 is a deficient number, since it is larger than the sum of its proper divisors (1).

536775122550113 is an equidigital number, since it uses as much as digits as its factorization.

536775122550113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6615000, while the sum is 53.

The spelling of 536775122550113 in words is "five hundred thirty-six trillion, seven hundred seventy-five billion, one hundred twenty-two million, five hundred fifty thousand, one hundred thirteen".