Base | Representation |
---|---|
bin | 110001111111111001… |
… | …110100001110010101 |
3 | 12010120102200110011111 |
4 | 301333321310032111 |
5 | 1334421440020401 |
6 | 40355053535021 |
7 | 3610242652354 |
oct | 617771641625 |
9 | 163512613144 |
10 | 53685470101 |
11 | 2084a05930a |
12 | a4a31a4471 |
13 | 50a7476c73 |
14 | 2853dab99b |
15 | 15e31dae51 |
hex | c7fe74395 |
53685470101 has 2 divisors, whose sum is σ = 53685470102. Its totient is φ = 53685470100.
The previous prime is 53685470071. The next prime is 53685470123. The reversal of 53685470101 is 10107458635.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51608480625 + 2076989476 = 227175^2 + 45574^2 .
It is a cyclic number.
It is not a de Polignac number, because 53685470101 - 231 = 51537986453 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53685470131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26842735050 + 26842735051.
It is an arithmetic number, because the mean of its divisors is an integer number (26842735051).
Almost surely, 253685470101 is an apocalyptic number.
It is an amenable number.
53685470101 is a deficient number, since it is larger than the sum of its proper divisors (1).
53685470101 is an equidigital number, since it uses as much as digits as its factorization.
53685470101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 40.
The spelling of 53685470101 in words is "fifty-three billion, six hundred eighty-five million, four hundred seventy thousand, one hundred one".
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