53715131143 has 2 divisors, whose sum is σ = 53715131144. Its totient is φ = 53715131142.

The previous prime is 53715131131. The next prime is 53715131147. The reversal of 53715131143 is 34113151735.

53715131143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53715131143 - 2¹⁷ = 53715000071 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53715131099 and 53715131108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53715131147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857565571 + 26857565572.

It is an arithmetic number, because the mean of its divisors is an integer number (26857565572).

Almost surely, 2^53715131143 is an apocalyptic number.

53715131143 is a deficient number, since it is larger than the sum of its proper divisors (1).

53715131143 is an equidigital number, since it uses as much as digits as its factorization.

53715131143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18900, while the sum is 34.

Adding to 53715131143 its reverse (34113151735), we get a palindrome (87828282878).

The spelling of 53715131143 in words is "fifty-three billion, seven hundred fifteen million, one hundred thirty-one thousand, one hundred forty-three".