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53715131207 is a prime number
BaseRepresentation
bin110010000001101010…
…111101101101000111
312010122111111101112222
4302001222331231013
51340002033144312
640402033402555
73611053040033
oct620152755507
9163574441488
1053715131207
1120864878121
12a4b110945b
1350b066090a
142857ccd1c3
1515e5ae9672
hexc81abdb47

53715131207 has 2 divisors, whose sum is σ = 53715131208. Its totient is φ = 53715131206.

The previous prime is 53715131147. The next prime is 53715131231. The reversal of 53715131207 is 70213151735.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 53715131207 - 26 = 53715131143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53715131237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857565603 + 26857565604.

It is an arithmetic number, because the mean of its divisors is an integer number (26857565604).

Almost surely, 253715131207 is an apocalyptic number.

53715131207 is a deficient number, since it is larger than the sum of its proper divisors (1).

53715131207 is an equidigital number, since it uses as much as digits as its factorization.

53715131207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22050, while the sum is 35.

The spelling of 53715131207 in words is "fifty-three billion, seven hundred fifteen million, one hundred thirty-one thousand, two hundred seven".