Base | Representation |
---|---|
bin | 11000011101011100000011… |
… | …11010110110111000010011 |
3 | 21001110002101001012102002022 |
4 | 30032232001322312320103 |
5 | 24022230414103402221 |
6 | 310221520313242055 |
7 | 14221026102010151 |
oct | 1416560172667023 |
9 | 231402331172068 |
10 | 53788055137811 |
11 | 16158427967825 |
12 | 604859aa0332b |
13 | 2402265601847 |
14 | d3d4da2bc3d1 |
15 | 63423dbb74ab |
hex | 30eb81eb6e13 |
53788055137811 has 2 divisors, whose sum is σ = 53788055137812. Its totient is φ = 53788055137810.
The previous prime is 53788055137793. The next prime is 53788055137829. The reversal of 53788055137811 is 11873155088735.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (53788055137793) and next prime (53788055137829).
It is a cyclic number.
It is not a de Polignac number, because 53788055137811 - 210 = 53788055136787 is a prime.
It is not a weakly prime, because it can be changed into another prime (53788055137711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26894027568905 + 26894027568906.
It is an arithmetic number, because the mean of its divisors is an integer number (26894027568906).
Almost surely, 253788055137811 is an apocalyptic number.
53788055137811 is a deficient number, since it is larger than the sum of its proper divisors (1).
53788055137811 is an equidigital number, since it uses as much as digits as its factorization.
53788055137811 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28224000, while the sum is 62.
The spelling of 53788055137811 in words is "fifty-three trillion, seven hundred eighty-eight billion, fifty-five million, one hundred thirty-seven thousand, eight hundred eleven".
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