Base | Representation |
---|---|
bin | 110010001000100101… |
… | …111110010100101011 |
3 | 12010221121000112011011 |
4 | 302020211332110223 |
5 | 1340221300413111 |
6 | 40421342444351 |
7 | 3613663122163 |
oct | 621045762453 |
9 | 163847015134 |
10 | 53831263531 |
11 | 20914388051 |
12 | a523b936b7 |
13 | 50cb732276 |
14 | 28694bd5a3 |
15 | 1600dd9021 |
hex | c8897e52b |
53831263531 has 2 divisors, whose sum is σ = 53831263532. Its totient is φ = 53831263530.
The previous prime is 53831263489. The next prime is 53831263571. The reversal of 53831263531 is 13536213835.
It is a happy number.
53831263531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an a-pointer prime, because the next prime (53831263571) can be obtained adding 53831263531 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 53831263531 - 215 = 53831230763 is a prime.
It is a super-2 number, since 2×538312635312 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (53831263571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26915631765 + 26915631766.
It is an arithmetic number, because the mean of its divisors is an integer number (26915631766).
Almost surely, 253831263531 is an apocalyptic number.
53831263531 is a deficient number, since it is larger than the sum of its proper divisors (1).
53831263531 is an equidigital number, since it uses as much as digits as its factorization.
53831263531 is an evil number, because the sum of its binary digits is even.
The product of its digits is 194400, while the sum is 40.
The spelling of 53831263531 in words is "fifty-three billion, eight hundred thirty-one million, two hundred sixty-three thousand, five hundred thirty-one".
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