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538737990613 is a prime number
BaseRepresentation
bin1111101011011110100…
…10010101101111010101
31220111120120120112022121
413311233102111233111
532311313411144423
61051254240455541
753631300235444
oct7655722255725
91814516515277
10538737990613
11198528607179
12884b231a5b1
133ba58907404
141c109d5cd5b
15e03193145d
hex7d6f495bd5

538737990613 has 2 divisors, whose sum is σ = 538737990614. Its totient is φ = 538737990612.

The previous prime is 538737990607. The next prime is 538737990619. The reversal of 538737990613 is 316099737835.

It is a balanced prime because it is at equal distance from previous prime (538737990607) and next prime (538737990619).

It can be written as a sum of positive squares in only one way, i.e., 277436065284 + 261301925329 = 526722^2 + 511177^2 .

It is a cyclic number.

It is not a de Polignac number, because 538737990613 - 29 = 538737990101 is a prime.

It is a super-2 number, since 2×5387379906132 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (538737990619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 269368995306 + 269368995307.

It is an arithmetic number, because the mean of its divisors is an integer number (269368995307).

Almost surely, 2538737990613 is an apocalyptic number.

It is an amenable number.

538737990613 is a deficient number, since it is larger than the sum of its proper divisors (1).

538737990613 is an equidigital number, since it uses as much as digits as its factorization.

538737990613 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25719120, while the sum is 61.

The spelling of 538737990613 in words is "five hundred thirty-eight billion, seven hundred thirty-seven million, nine hundred ninety thousand, six hundred thirteen".