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53874025141 is a prime number
BaseRepresentation
bin110010001011001001…
…000110001010110101
312011001120111001001111
4302023021012022311
51340313222301031
640425511155021
73615022441456
oct621311061265
9164046431044
1053874025141
1120936534522
12a536375a71
135107554ab1
14287105112d
151604a341b1
hexc8b2462b5

53874025141 has 2 divisors, whose sum is σ = 53874025142. Its totient is φ = 53874025140.

The previous prime is 53874025129. The next prime is 53874025181. The reversal of 53874025141 is 14152047835.

It is an a-pointer prime, because the next prime (53874025181) can be obtained adding 53874025141 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 43491434116 + 10382591025 = 208546^2 + 101895^2 .

It is a cyclic number.

It is not a de Polignac number, because 53874025141 - 233 = 45284090549 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 53874025094 and 53874025103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53874025181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26937012570 + 26937012571.

It is an arithmetic number, because the mean of its divisors is an integer number (26937012571).

Almost surely, 253874025141 is an apocalyptic number.

It is an amenable number.

53874025141 is a deficient number, since it is larger than the sum of its proper divisors (1).

53874025141 is an equidigital number, since it uses as much as digits as its factorization.

53874025141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 134400, while the sum is 40.

The spelling of 53874025141 in words is "fifty-three billion, eight hundred seventy-four million, twenty-five thousand, one hundred forty-one".