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54000122104309 is a prime number
BaseRepresentation
bin11000100011100111000100…
…00110001000100111110101
321002012100202100121111200211
430101303202012020213311
524034214222224314214
6310503151424305421
714242244236331413
oct1421634206104765
9232170670544624
1054000122104309
111622a361169507
126081703772271
132419260901384
14d49896c502b3
15639a016d90c4
hex311ce21889f5

54000122104309 has 2 divisors, whose sum is σ = 54000122104310. Its totient is φ = 54000122104308.

The previous prime is 54000122104277. The next prime is 54000122104381. The reversal of 54000122104309 is 90340122100045.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 53990311796100 + 9810308209 = 7347810^2 + 99047^2 .

It is a cyclic number.

It is not a de Polignac number, because 54000122104309 - 25 = 54000122104277 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (54000122104109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27000061052154 + 27000061052155.

It is an arithmetic number, because the mean of its divisors is an integer number (27000061052155).

Almost surely, 254000122104309 is an apocalyptic number.

It is an amenable number.

54000122104309 is a deficient number, since it is larger than the sum of its proper divisors (1).

54000122104309 is an equidigital number, since it uses as much as digits as its factorization.

54000122104309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 31.

The spelling of 54000122104309 in words is "fifty-four trillion, one hundred twenty-two million, one hundred four thousand, three hundred nine".