Base | Representation |
---|---|
bin | 11000100011100111000100… |
… | …00110001000101000111101 |
3 | 21002012100202100121111210111 |
4 | 30101303202012020220331 |
5 | 24034214222224320011 |
6 | 310503151424310021 |
7 | 14242244236331545 |
oct | 1421634206105075 |
9 | 232170670544714 |
10 | 54000122104381 |
11 | 1622a361169572 |
12 | 6081703772311 |
13 | 241926090140b |
14 | d49896c50325 |
15 | 639a016d9121 |
hex | 311ce2188a3d |
54000122104381 has 2 divisors, whose sum is σ = 54000122104382. Its totient is φ = 54000122104380.
The previous prime is 54000122104309. The next prime is 54000122104387. The reversal of 54000122104381 is 18340122100045.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 53735262628356 + 264859476025 = 7330434^2 + 514645^2 .
It is a cyclic number.
It is not a de Polignac number, because 54000122104381 - 223 = 54000113715773 is a prime.
It is a super-2 number, since 2×540001221043812 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54000122104387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27000061052190 + 27000061052191.
It is an arithmetic number, because the mean of its divisors is an integer number (27000061052191).
Almost surely, 254000122104381 is an apocalyptic number.
It is an amenable number.
54000122104381 is a deficient number, since it is larger than the sum of its proper divisors (1).
54000122104381 is an equidigital number, since it uses as much as digits as its factorization.
54000122104381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 31.
The spelling of 54000122104381 in words is "fifty-four trillion, one hundred twenty-two million, one hundred four thousand, three hundred eighty-one".
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