Base | Representation |
---|---|
bin | 1010000011110011… |
… | …10111010100110001 |
3 | 111221101021201002221 |
4 | 11001321313110301 |
5 | 42030031431103 |
6 | 2251522441041 |
7 | 250555545205 |
oct | 50171672461 |
9 | 14841251087 |
10 | 5400655153 |
11 | 2321590173 |
12 | 1068803181 |
13 | 680b6c44a |
14 | 393396b05 |
15 | 2191e91bd |
hex | 141e77531 |
5400655153 has 2 divisors, whose sum is σ = 5400655154. Its totient is φ = 5400655152.
The previous prime is 5400655151. The next prime is 5400655157. The reversal of 5400655153 is 3515560045.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4795839504 + 604815649 = 69252^2 + 24593^2 .
It is a cyclic number.
It is not a de Polignac number, because 5400655153 - 21 = 5400655151 is a prime.
Together with 5400655151, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (5400655151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2700327576 + 2700327577.
It is an arithmetic number, because the mean of its divisors is an integer number (2700327577).
Almost surely, 25400655153 is an apocalyptic number.
It is an amenable number.
5400655153 is a deficient number, since it is larger than the sum of its proper divisors (1).
5400655153 is an equidigital number, since it uses as much as digits as its factorization.
5400655153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45000, while the sum is 34.
The square root of 5400655153 is about 73489.1498998322. The cubic root of 5400655153 is about 1754.4815911324.
The spelling of 5400655153 in words is "five billion, four hundred million, six hundred fifty-five thousand, one hundred fifty-three".
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